MySQL DATE_FORMAT() Function
Definition and Usage
The DATE_FORMAT() function formats a date as specified.
Syntax
DATE_FORMAT(date, format)
Parameter Values
| Parameter |
Description |
| date |
Required. The date to be formatted |
| format |
Required. The format to use. Can be one or a
combination of the following values:
| Format |
Description |
| %a |
Abbreviated weekday name (Sun to Sat) |
| %b |
Abbreviated month name (Jan to Dec) |
| %c |
Numeric month name (0 to 12) |
| %D |
Day of the month as a numeric value, followed by suffix (1st, 2nd, 3rd,
...) |
| %d |
Day of the month as a numeric value (01 to 31) |
| %e |
Day of the month as a numeric value (0 to 31) |
| %f |
Microseconds (000000 to 999999) |
| %H |
Hour (00 to 23) |
| %h |
Hour (00 to 12) |
| %I |
Hour (00 to 12) |
| %i |
Minutes (00 to 59) |
| %j |
Day of the year (001 to 366) |
| %k |
Hour (0 to 23) |
| %l |
Hour (1 to 12) |
| %M |
Month name in full (January to December) |
| %m |
Month name as a numeric value (00 to 12) |
| %p |
AM or PM |
| %r |
Time in 12 hour AM or PM format (hh:mm:ss AM/PM) |
| %S |
Seconds (00 to 59) |
| %s |
Seconds (00 to 59) |
| %T |
Time in 24 hour format (hh:mm:ss) |
| %U |
Week where Sunday is the first day of the week (00 to 53) |
| %u |
Week where Monday is the first day of the week (00 to 53) |
| %V |
Week where Sunday is the first day of the week (01 to 53). Used with %X |
| %v |
Week where Monday is the first day of the week (01 to 53). Used with %x |
| %W |
Weekday name in full (Sunday to Saturday) |
| %w |
Day of the week where Sunday=0 and Saturday=6 |
| %X |
Year for the week where Sunday is the first day of the week. Used with
%V |
| %x |
Year for the week where Monday is the first day of the week. Used with
%v |
| %Y |
Year as a numeric, 4-digit value |
| %y |
Year as a numeric, 2-digit value |
|
Technical Details
More Examples
Example
Format a date:
SELECT DATE_FORMAT("2017-06-15", "%M %d %Y");
Try it Yourself »
Example
Format a date:
SELECT DATE_FORMAT("2017-06-15", "%W %M
%e %Y");
Try it Yourself »
Example
Format a date:
SELECT DATE_FORMAT(BirthDate, "%W %M %e %Y") FROM Employees;
Try it Yourself »